Very easy! Make the lady guest sit in the drawing room and enter the kitchen......... How do women manage to hide from other women???:noidea:
WOW! What a nice point to ponder!! :madgrin:When one goes in search of Honey, he must not forget that he gets stung by Bees. .....
I have done a few times to save a :fish2: by the members of this forum.I am recycling/ recirculating my posts. ...........
just for a change of topic and to keep myself as a posting member and keeping in mind the desirability to increase the traffic in this thread, and knowing that many take a random walk in this thread, and any posting can be made with impunity, how about solving this maths quiz?
If a + b + c + d = a x b x c x d
find the value of a, b, c, d
N.B.: 1.decimal places allowed correct upto second digit
2. I do not know the solution (even if there is one!!)
I am sure it will work 0, but will give it some thought
just for a change of topic and to keep myself as a posting member and keeping in mind the desirability to increase the traffic in this thread, and knowing that many take a random walk in this thread, and any posting can be made with impunity, how about solving this maths quiz?
If a + b + c + d = a x b x c x d
find the value of a, b, c, d (for values other than zero)
N.B.: 1.decimal places allowed correct upto second digit
2. I do not know the solution (even if there is one!!)
I am sure it will work 0, but will give it some thought
Let us suppose that
a = 1/ sq.root of 2
b = (-) 1/ sq root of 2.
c = + 2 and
d = (-) 1.
So a+ b+ c+ d = (1/sq root of 2) + (- 1/ sq root of 2) + 2 (- 1) = 1.
a.b.c.d = 1/ sq root of 2 x (- 1/ sq. root of 2) x (2) (-1) =
(- 1/2) x 2 X (-1) = 1.
L.H.S + R.H.S.
Yahooooooooooooooooo!