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Raji Ram
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:thumb: Given!!
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Puzzle time!
- Thread starter Raji Ram
- Start date
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nkripashankar
Active member
888+88+8+8+8
mskmoorthy
Active member
What is the solution to this cryptarithm (Each distinct letter represents a distinct digit 0 through 9)
AAA+
AA+
A+
A+
A
------------
BCCC
-----------
AAA+
AA+
A+
A+
A
------------
BCCC
-----------
mskmoorthy
Active member
I just made up that question subtly revealing that I know the answer to question posed by RR Madam
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Raji Ram
Active member
கொஞ்சம் தமிழின் பக்கம் திரும்புவோம்!
சி வா ஜி
வா யி லே
ஜி லே பி (makes sense!)
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க ர டி
ர யி ல்
டி ல் லி (just words!)
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இவை சிறு வயதில் நாம் பலர் விரும்பியது.
1. ப த வி; 2. ப கு தி; 3. ச க தி ............... இவற்றில் முயலுங்களேன்!
சி வா ஜி
வா யி லே
ஜி லே பி (makes sense!)
---------------------
க ர டி
ர யி ல்
டி ல் லி (just words!)
---------------------
இவை சிறு வயதில் நாம் பலர் விரும்பியது.
1. ப த வி; 2. ப கு தி; 3. ச க தி ............... இவற்றில் முயலுங்களேன்!
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Raji Ram
Active member
This post appeared a little late. Noted it only now! :ranger:
:thumb: for the correct answer!
Hi raji ram sir I don't understand Tamil.say it in English for me
OP
OP
Raji Ram
Active member
The fun will be lost when translated to English. Anyway, since you asked for it, I am giving the transliteration.
mirAsu; rAgam; summA are the three words used and I tried to get some meaning out of this.a b c
b d e
c e f
மி ரா சு
ரா க ம்
சு ம் மா
Hence 'mirAsu rAgam pAdinAl summA kaithattal ezhumbAdhu?'
prasad1
Active member
[h=1]What Is 6÷2(1+2) = ? The Correct Answer Explained[/h]Posted August 31, 2016 By Presh Talwalkar
[FONT="]What is 6÷2(1+2) = ?
[FONT="]The problem often generates debate and has millions of comments on Facebook, Twitter, YouTube and other social media sites.[/FONT]
[/FONT]
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Raji Ram
Active member
What is 6÷2(1+2) = ? The Correct Answer Explained - YouTube
So this video proves that I am historical!! :lol:
So this video proves that I am historical!! :lol:
prasad1
Active member
I too got the same result. I guess we are dinosaurs.
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Raji Ram
Active member
ound:mskmoorthy
Active member
Here are a few more along the same lines. What are the values of
a) 2-3+4
b) 2-3-4
c) 2[SUP]2[SUP]3[/SUP][/SUP]
a) 2-3+4
b) 2-3-4
c) 2[SUP]2[SUP]3[/SUP][/SUP]
mskmoorthy
Active member
what is the value of
(1+9[SUP]-4[SUP]6*7[/SUP][/SUP])[SUP]3[SUP]2[SUP]85[/SUP][/SUP][/SUP]
(1+9[SUP]-4[SUP]6*7[/SUP][/SUP])[SUP]3[SUP]2[SUP]85[/SUP][/SUP][/SUP]
mskmoorthy
Active member
Sorry for being pedantic
I looked at the video given in post https://www.tamilbrahmins.com/showthread.php?t=31366&p=385084#post385084. That is not the way a value of an expression is computed. The order of evaluation is always left to right according to the operator precedence.
So in 6/2*(1+2) since / and * are the same precedence 6/2 is evaluated first giving 3. Now next two operators * and + , plus inside parenthesis, so 1+2 is evaluated next and finally the results of the first two operations are multiplied. Postfix notation (what the pocket calculator does) for this expression is 6, 2, / ,1 ,2 ,+ ,*
Answers to my questions in post https://www.tamilbrahmins.com/showthread.php?t=31366&p=385150#post385150
a) 3 ( 2,3,-,4,+)
b) -5 (2,3,-4, -)
c) 256 (2,2,3,^,^) - Exponentiation (operator ^) is right associative - you go from right to left - so 2[SUP]3[/SUP] is evaluated first to 8 then 2[SUP]8[/SUP] is evaluated next to get 256.
For details on associativity of operators please see https://en.wikipedia.org/wiki/Operator_associativity
Answer to https://www.tamilbrahmins.com/showthread.php?t=31366&p=385151#post385151
is roughly 2.71 (value of e) - to see this note 4[SUP]6*7[/SUP] is evaluated first to 4[SUP]42[/SUP].
Since 4 = 2[SUP]2[/SUP]. Hence 4[SUP]42[/SUP] becomes 2[SUP]84[/SUP]. next 9[SUP]-2[SUP]84[/SUP] [/SUP]becomes
1/9[sup]2[SUP]84[/SUP][/sup]. Since 9=3[SUP]2[/SUP] that expression becomes 1/3[SUP]2[SUP]85[/SUP][/SUP].
So the expression is of the form (1+1/n)[SUP]n[/SUP] where n =3[SUP]2[SUP]85[/SUP][/SUP]
Since n is very large, from your calculus 1, we know that it becomes Euler's number e = 2.71...
( https://en.wikipedia.org/wiki/E_(mathematical_constant) )
By the same token the value of (1.001)[SUP]1000[/SUP] will be approximately 2.71 (verified here http://www.wolframalpha.com/input/?i=1.001^1000 )
Going back in the past the question I raised (two years ago ) here https://www.tamilbrahmins.com/showthread.php?t=26588&p=311655#post311655 (You have to mouse over to get the puzzle )- what is the value of 0.999 [SUP]1000[/SUP] will be approximately 0.367 which is 1/e (verified here http://www.wolframalpha.com/input/?i=0.999^1000 )
I looked at the video given in post https://www.tamilbrahmins.com/showthread.php?t=31366&p=385084#post385084. That is not the way a value of an expression is computed. The order of evaluation is always left to right according to the operator precedence.
So in 6/2*(1+2) since / and * are the same precedence 6/2 is evaluated first giving 3. Now next two operators * and + , plus inside parenthesis, so 1+2 is evaluated next and finally the results of the first two operations are multiplied. Postfix notation (what the pocket calculator does) for this expression is 6, 2, / ,1 ,2 ,+ ,*
Answers to my questions in post https://www.tamilbrahmins.com/showthread.php?t=31366&p=385150#post385150
a) 3 ( 2,3,-,4,+)
b) -5 (2,3,-4, -)
c) 256 (2,2,3,^,^) - Exponentiation (operator ^) is right associative - you go from right to left - so 2[SUP]3[/SUP] is evaluated first to 8 then 2[SUP]8[/SUP] is evaluated next to get 256.
For details on associativity of operators please see https://en.wikipedia.org/wiki/Operator_associativity
Answer to https://www.tamilbrahmins.com/showthread.php?t=31366&p=385151#post385151
is roughly 2.71 (value of e) - to see this note 4[SUP]6*7[/SUP] is evaluated first to 4[SUP]42[/SUP].
Since 4 = 2[SUP]2[/SUP]. Hence 4[SUP]42[/SUP] becomes 2[SUP]84[/SUP]. next 9[SUP]-2[SUP]84[/SUP] [/SUP]becomes
1/9[sup]2[SUP]84[/SUP][/sup]. Since 9=3[SUP]2[/SUP] that expression becomes 1/3[SUP]2[SUP]85[/SUP][/SUP].
So the expression is of the form (1+1/n)[SUP]n[/SUP] where n =3[SUP]2[SUP]85[/SUP][/SUP]
Since n is very large, from your calculus 1, we know that it becomes Euler's number e = 2.71...
( https://en.wikipedia.org/wiki/E_(mathematical_constant) )
By the same token the value of (1.001)[SUP]1000[/SUP] will be approximately 2.71 (verified here http://www.wolframalpha.com/input/?i=1.001^1000 )
Going back in the past the question I raised (two years ago ) here https://www.tamilbrahmins.com/showthread.php?t=26588&p=311655#post311655 (You have to mouse over to get the puzzle )- what is the value of 0.999 [SUP]1000[/SUP] will be approximately 0.367 which is 1/e (verified here http://www.wolframalpha.com/input/?i=0.999^1000 )
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